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1=x^2+9x+7
We move all terms to the left:
1-(x^2+9x+7)=0
We get rid of parentheses
-x^2-9x-7+1=0
We add all the numbers together, and all the variables
-1x^2-9x-6=0
a = -1; b = -9; c = -6;
Δ = b2-4ac
Δ = -92-4·(-1)·(-6)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{57}}{2*-1}=\frac{9-\sqrt{57}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{57}}{2*-1}=\frac{9+\sqrt{57}}{-2} $
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